Question

9q^4r^4-6p^4q^2r^2+p^8
factorize it
for the brilliant people in maths can do this with process​

Answer 1

Answer:

Required factorised form is ( p^4 - 3 q^2 r^2 )^2.

Step-by-step explanation:

= > 9q^4 r^4 - 6p^4 q^2 r^2 + p^8

= > p^8 + 9q^4 r^4 - 6p^4 q^2 r^2

= > ( p^4 )^2 + 3^2 q^4 r^4 - 2 x 3 p^4 q^2 r^2

= > ( p^4 )^2 + ( 3 q^2 r^2 )^2 - 2( p^4 x 3 q^2 r^2 )

From the properties of factorisation :

• a^2 + b^2 - 2ab = ( a - b )^2

= > ( p^4 - 3 q^2 r^2 )^2

Hence the required factorised form is ( p^4 - 3 q^2 r^2 )^2.

Answer 2

Answer:

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