Question

9tan square A - 9 sec square A

Answer 1

Friend, here's your answer➡️➡️➡️
$9 { \tan }^{2} x - 9 { \sec }^{2}x \\ = - 9( { \sec }^{2}x - { \tan}^{2} x) \\ = - 9 \times 1 \\ = - 9$

Answer 2

9tan^2A - 9sec^2A
= -9( -tan^2A+sec^2A)
= -9(Sec^2A -tan^2A)
=-9×1
=-9
Ans