9th term of an ap is zero then show that its 29th term is double of its 19th term
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Given:
a9 = a + 8d = 0 ——> 1
a19 = a + 18d
a19 = a + 8d + 10d
a19 = 10d ——> 2 (from 1)
a29 = a + 28d
a29 = a + 8d + 20d
a29 = 20d (from 1)
a29 = 2*10d = 2*a19
a29 = 2*a19 ——> Answer
a9 = a + 8d = 0 ——> 1
a19 = a + 18d
a19 = a + 8d + 10d
a19 = 10d ——> 2 (from 1)
a29 = a + 28d
a29 = a + 8d + 20d
a29 = 20d (from 1)
a29 = 2*10d = 2*a19
a29 = 2*a19 ——> Answer
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