Question

Three identical thin rods each of length l and mass m are joined together to form a letter h

Answer 1

Answer:

Moment of interia is  = 4Ml²/3

Explanation:

Complete question statement is;

Three identical thin rtods each of length l and mass M are joined together to from a letter. H. What is the moment of inertia of the system about one of the sides of H?

Solution;

Moment of inertia about one of its side will be the addition of

moment of inertia of each rod about the side..  

hence now moment of inertia about the first rod about its own axis is zero because its radius is zero..

now MOI of the second rod about its end is Ml²/3 and

that of the third rod about the first is Ml²

hence moment of inertia of the body is;

I tot = I1 + I2 + I3

     =  0 + Ml²/3 + Ml²

      = 4Ml²/3