9th to the power 68/7th to the power 68
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Answered by
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Step-by-step explanation:
9^68 (mod 4)={9 (mod 4)}^68={1 (mod 4)}^68=1
7^68 (mod 4)={7 (mod 4)}^68={ -1 (mod 4)^68=1
(Since 68 is EVEN )
The above is computed in light of Exponent Law a^k (mod n)=(a(mod n))^k
(where a,k,n are integers).
Coming to the question,
9^68 (mod 4) - 7^68 (mod 4)= 1–1 = 0 ANSWER.
Answer = 0
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