Question

9x^3y+41x^2y+20xy^3​

Answer 1

what we have to do in this question??

Answer 2

Step-by-step explanation:

Given:

taking out xy as common ,xy(9x^2+41x+20y^2)

Using,

splitting middle term

so xy(9x^2+36xy+5xy+20y^2)

since grouping together

xy[9x^2+36xy+5xy+20y^2]

so

taking out common

xy[9x(x+4)+5y(x+4)]

xy(9x+5y)(x+4)

so

the factor are xy (9x+5y)(x+4)

make it as brainlist