Question

9x/7-6x=5
please solve the above question with explanation​

Answer 1

$\frac{9x}{7 - 6x} = 5 \\ \\ \geqslant 9x = 5(7 - 6x)(cross \: multiple) \\ \geqslant 9x = 35 - 30x \\ \geqslant 9x + 30x = 35 \\ \geqslant 39x = 35 \\ \geqslant x = \frac{35}{39}$

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Answer 2

Answer:

$=>x=-\frac{35}{33}$

Step-by-step explanation:

Given that:-

$\frac{9x}{7-6x}=5$

To find:- The value of the expression:

Here we will use the transposition method.

First of all, we have to identify the variables and the constants.

Then solve the expression of both sides by using various mathematical operations.

As we have,

=> $\frac{9x}{7-6x}=5$

For that, first of all, we have to find the common denominator:

=> $\frac{9x}{7}-\frac{7(-6)x}{7} =5$

$=> \frac{9x+7(-6)x}{7} =5$

$=> \frac{9x-42x}{7} =5$

Combine like terms, we get

=> $\frac{-33x}{7}=5$

Now, multiply both sides by $7$ we get

=> $\frac{-33x}{7}\times 7=5\times 7$

=> $-33x =35$

Divide both sides by $-33$, we get

$=>x=-\frac{35}{33}$

Hence, the required solution is $-\frac{35}{33}.$