9x+7y=55 , 7x+9y=57 std 10
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Answered by
12
Hey!!!
Good Afternoon
________
We have
9x + 7y = 55
7x + 9y = 57
You see the pair of Equation is in the form
ax + by = c
bx + ay = d
Thus a = 9 , b = 7 , c = 55 and d = 57
See this is the method you'll not find anywhere else
Thus
Thus
Thus x - y = -1-----(1)
Similarly
Thus
Thus
x + y = 112/16
=> x + y = 7-----(2)
Add (1) and (2)
=> x + y + x - y = 7 - 1
=> 2x = 6
=> x = 3
Using x in (2)
=> x + y = 7
=> y = 4
Thus x = 3 and y = 4
__________
Hope this helps ✌️
Good Afternoon
________
We have
9x + 7y = 55
7x + 9y = 57
You see the pair of Equation is in the form
ax + by = c
bx + ay = d
Thus a = 9 , b = 7 , c = 55 and d = 57
See this is the method you'll not find anywhere else
Thus
Thus
Thus x - y = -1-----(1)
Similarly
Thus
Thus
x + y = 112/16
=> x + y = 7-----(2)
Add (1) and (2)
=> x + y + x - y = 7 - 1
=> 2x = 6
=> x = 3
Using x in (2)
=> x + y = 7
=> y = 4
Thus x = 3 and y = 4
__________
Hope this helps ✌️
Answered by
17
Heya user☺☺
Using the simple method of elemination , we get
9x+7y=55
+ 7x+9y=57
---------------------
16(x+y) = 112
x+y=7 .........eq1
Now reducing x, we get
9x+7y=55
- 9x+9y=63
-------------------
-2y = -8
y = 4 ..........eq2
Putting value of y in eq1, we get
x= 3
so, x=3 and y=4.
Hope this will help you☺☺
Using the simple method of elemination , we get
9x+7y=55
+ 7x+9y=57
---------------------
16(x+y) = 112
x+y=7 .........eq1
Now reducing x, we get
9x+7y=55
- 9x+9y=63
-------------------
-2y = -8
y = 4 ..........eq2
Putting value of y in eq1, we get
x= 3
so, x=3 and y=4.
Hope this will help you☺☺
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