Question

9x/8+1=10
$\frac{9x}{8} + 1 = 10$

Answer 1

$\boxed{\underline{\huge{Question}}}$ :-

$\bf{\frac{9x}{8}} + 1$ = $\bf{10}$

$\boxed{\underline{\huge{solution}}}$ = $\bf{\huge{8}}$

$\underline{\mathbb{Explanation}}$ :-

Firstly, take 1 to other side as it is positive so taking other side it will become negative!

=> $\bf{\frac{9x}{8}}$ = $\bf{10 - 1}$

subtract the terms ,

=> $\bf{\frac{9x}{8}}$ = $\bf{9}$

now, take the fraction ; $\bf{\frac{9}{8}}$ to other side , so that they will become reverse , i.e., $\bf{\frac{8}{9}}$

=> $\bf{x}$ = $\bf{9 \times {\frac{8}{9}}}$

so , 9 ÷ 9 = 1 , then both 9 will cancel out!

=> $\bf{\boxed{x = 8}}$ (Answer!)

★$\mathcal{\huge{\underline{Be\: Brainly}}}$★

Answer 2

Your Question is

$\sf{\frac{9x}{8} + 1 = 10}$

Find the value of x.


Here's the answer -

Now,

Let's take 1 to R .H .S, where it's sign will become negative

$\sf {\frac{9x}{8} = 10 - 1}$

$\sf{\frac{9x}{8} = 9}$


Now,

Let's take the denominator 8 to the R. H. S where it will get multiplied by 9

$\sf{9x = 9 \times 8}$

$\sf{9x = 72}$

Now,

Dividing both sides by 9,

$\sf{ \frac{9x}{9 } = \frac{72}{9}}$

${\sf {\boxed{x = 8}}}$

Thus,

Value of x is 8.


Thanks!