Question

9x²-12x+20=0
Solve by factorization method class 11

Answer 1

here is ur answer hope it helps

Answer 2

AnswEr:

We have,

$\\ \qquad \implies \tt 9 {x}^{2} - 12 + 20 = 0 \\ \\ \\ \implies \tt \: 9 {x}^{2} - 12x + 4 + 16 = 0 \\ \\ \\ \implies \tt \: {(3x - 2)}^{2} + 16 = 0 \\ \\ \\ \implies \tt \: {(3x - 2)}^{2} - 16 {i}^{2} = 0 \\ \\ \\ \implies \tt \: [(3x - 2) + 4i] \: \: [(3x - 2) - 4i] = 0 \\ \\ \\ \implies \tt \: (3x - 2 + 4i)(3x - 2 - 4i) = 0 \\ \\ \\ \implies \tt \: 3x - 2 + 4i = 0, \: or \: \: 3x - 2 - 4i = 0 \\ \\ \\ \implies \tt \: 3x = 2 - 4i, \: or \: \: 3x = 2 + 4i \\ \\ \\ \implies \tt \: x = \frac{2}{3} - \frac{4}{3} i \: \: \: or \: \: \: x = \frac{2}{3} + \frac{4}{3} i \\ \\ \\ \rm \: Hence, \: the \: roots \: of \: the \: given \: equation \: are \\ \\ \rm \: \frac{2}{3} - \frac{4}{3} i \: \: and \: \: \: \frac{2}{3}i + \frac{4}{3} i$