please answer my above question and you will get brainliest answer and maximum points I can offer
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heya.....
1.6765201
(a) Prime factorization of 6765201
= 3^4 * 17^4
= (3 * 17)^4
= (51)^4.
(b). Prime factorization of 6765206
= 2^1 * 7^1 * 483229^1.
(c) Prime factorization of 6765207
= 3^1 * 29^1 * 77761^1
(d)Prime factorization of 6765209
= 11^1 * 615019^1.
Therefore the fourth power of natural number = 6476201 i.e 51
Hope this helps!
tysm.....@GOZMIT
1.6765201
(a) Prime factorization of 6765201
= 3^4 * 17^4
= (3 * 17)^4
= (51)^4.
(b). Prime factorization of 6765206
= 2^1 * 7^1 * 483229^1.
(c) Prime factorization of 6765207
= 3^1 * 29^1 * 77761^1
(d)Prime factorization of 6765209
= 11^1 * 615019^1.
Therefore the fourth power of natural number = 6476201 i.e 51
Hope this helps!
tysm.....@GOZMIT
shivam945:
why could not the option II will be the right answer because in option second the last digit is 6 and the answer you stated above say that the last digit should be contain 0,1,5,6
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HEYA ! !
ANSWER IN THE ATTACHMENT
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ANSWER IN THE ATTACHMENT
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