9x²-64 find zeros of polynomial
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Answered by
2
9x^2 - 64 = 0
(3x)^2 - (8)^2 =0
(3x+8)(3x-8) = 0
x = ± 8/3
(3x)^2 - (8)^2 =0
(3x+8)(3x-8) = 0
x = ± 8/3
Answered by
0
9x2+0x-64.
9x2+24x-24x-64
in this way solve by mid term split method.
9x2+24x-24x-64
in this way solve by mid term split method.
pratik89:
yes but answer is 1,-9/2
is this question given in guide
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