Question

A 0.040 kg ball tied to a string moves at a constant speed of 2.7 m/s in a circle that has a radius of a 0.500 m.

What is the magnitude of the centripetal force acting on the ball at the position shown?​

Answer 1

Given:-

• Mass of ball tied, m = 0.040 kg
• Constant speed of ball moving in circular path, v = 2.7 m/s
• Radius of circular path, r = 0.500 m

To find:-

• Magnitude of centripetal force acting on the ball, F =?

Formula required:-

• Formula for centripetal acceleration

        F = m v² / r

Where F is centripetal force (In newtons), m is mass of body (In kg), v is constant speed or can be said tangential velocity of body (In m/s) and r is the radius (in metres).

Solution:-

Using formula for centripetal acceleration

→ F = m v² / r

→ F = ( 0.040 ) × ( 2.7 )² / 0.500

→ F = 0.04 × 2.7 × 2.7 / 0.5

→ F = 2 × 0.04 × 2.7 × 2.7

→ F = 0.5832 N

Therefore,

• Magnitude of centripetal acceleration on the ball is 0.5832 Newtons.

Answer 2

Answer:

0.5832

Explanation:

Given:

m=0.040

r=0.5

v=2.7

Solution:

centripetal force=mv^2/r

=(0.040×2.7×2.7)/0.5

=0.2916/0.5

=0.5832