Question

A 0.05 kg bullet travelling at 500 ms-1

horizontally strikes a thick wall. It stops after

penetrating through the wall at horizontal

distance of 0.25m. What is the magnitude of

the average force the wall exerts on the

bullet?
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Answer 1

Answer:

Explanation:

Use the fundamental equation of motion ,

v^2 - u^2 = 2ad.

u= 20m/s

v= 0m/s

d =0.05 m.

From these a = - 4,000 m/s^2