Physics, asked by sanidhyadimathur, 6 months ago

a 0.1 kg bullet acquires a speed of 840 m/s in a gun barrel 1.5m long. What is the average force exerted on the bullet?

Answers

Answered by asaph24310

0

Answer:

47040 N

Explanation:

F x T = MV - O

F= 0.1 x 840 / 1/560

=47040

Answered by juzermorud2005

0

F=ma
=0.1*840
=84N
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