Chemistry, asked by shahadkt123, 1 year ago

A 0.1 molar solution of K4[Fe(CN)6] is 46% ionised at 18°C. Calculate its osmotic pressure

Answers

Answered by himanshurao24462
0

0 0000000000000ⁿ000099099990000000000000

Answered by 22ericksoncami
0

Homework Set 2.1 Solutions

Ch. 6: 8, 15-17, 19, 23, 25, 33, 36, 44, 49

8. For the reaction HCO3- ↔ H+ + CO32-, ΔG°  = +59kJ/mol at 298.15K.  Find the value of K for the reaction.

K = exp(-ΔG°/RT) = exp(-59000 J mol-1/(8.314 J mol-1 K-1*298.15 K)) = 5 x 10-11.

15.  What concentration of Fe(CN)64- (ferrocyanide) is in equilibrium with 1.0 μM Ag+ and Ag4Fe(CN)6(s).  Express your answer with a prefix from table 1-3.

Since it states “in equilibrium with”, no ICE table is needed.

Ksp = [Ag+]4[Fe(CN)64-]  =  8.5 x 10-45  = (1.0 x 10-6)4*x

x = 8.5 x 10-45/1.0 x 10-24  = 8.5 x 10-21 M = 8.5 zM = [Fe(CN)64-]

16.  Find [Cu2+] in a solution saturated with Cu4(OH)6(SO4) if [OH-] is fixed at 1.0 x 10-6 M.  Note that Cu4(OH)6(SO4) gives 1 mole of SO42- for 4 mol Cu2+.

                       Cu4(OH)6(SO4)(s) ↔ 4Cu2+ + 6OH- + SO42-       Ksp = 2.3 x  10-69

Initial                                                    0      1.0 x 10-6     0

Change                                                 +4x      +6x          +x

Equilibrium                                           4x    1.0 x 10-6     +x    (1.0 x 10-6 is fixed)

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