Question

A 0.1539 molal aqueous solution of cane sugar (mol mass =342gmol−1) has a freezing point of 271K while the freezing point of pure water is 273.15K.What will be the freezing point of an aqueous solution containing 5g of glucose (mol mass =180gmol−1) per 100g of solution.

Answer 1

Answer:

Explanation:

Refer the below attachment.