Question

A 0.24 g sample of compound of oxygen and boron was found
by analysis to contain 0.096 g of boron and 0.144 g of oxygen.
Calculate the percentage composition of the compound by
weight.​

Answer 1

Answer:

Boron percentage = 40%

Oxygen percentage = 60%

Explanation:

It is very simple.

Divide the given mass of boron and oxygen by weight of compound and multiply it with 100.

=> Percentage composition of Boron:

B% = (0.096/024)*100 = 40%

=> Percentage composition of Oxygen:

O% = (0.144/0.24)*100 = 60%

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