A 0.24 g sample of compound of oxygen and boron was found
by analysis to contain 0.096 g of boron and 0.144 g of oxygen.
Calculate the percentage composition of the compound by
weight.
Answers
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5
Answer:
Boron percentage = 40%
Oxygen percentage = 60%
Explanation:
It is very simple.
Divide the given mass of boron and oxygen by weight of compound and multiply it with 100.
=> Percentage composition of Boron:
B% = (0.096/024)*100 = 40%
=> Percentage composition of Oxygen:
O% = (0.144/0.24)*100 = 60%
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