In the given figure if PQ||RS prove that
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From the triangles POQ & ROS above,
<POQ=<ROS (vertically opposite angles)
<QPO=<RSO (alternate angles)
<QPO = <SRO(alternate angles)
Therefore, triangle POQ=triangle ROS (PROVED by AAA similarity)
Therefore by cpct(common parts of congruent triangles) PQ ||RS
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Explanation:
Since PQ || RS, hence PS is a traversal:
=> angle QPS = angle RSP ---(a)
Now similarly, QR is a traversal:
=> angle PQR = angle SRQ ---(b)
Now, we can clearly see that,
angle POQ = angle SOR (vertically opposite angles) --(c)
Hence from (a), (b) and (c), We can say:
∆POQ ~ ∆SOR (AAA similarity)
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