A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Answers
Total mass of compound = 0.24 g
Mass of boron in it = 0.096 g
Therefore % composition by weight of boron = (Mass of boron/ Total mass of compound)*100
= (0.096/0.24)*100
= 40 %
Mass of oxygen in the compound = 0.144 g
Therefore % composition by weight of oxygen = (Mass of oxygen/ Total mass of compound)*100
= (0.144/0.24)*100
= 60 %.
The compound is made up of only boron and oxygen, therefore the % composition of the componenets sum to 100% (60% + 40%)
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Answer:
Total mass of compound = 0.24 g
Mass of boron in it = 0.096 g
Therefore % composition by weight of boron = (Mass of boron/ Total mass of compound)*100
= (0.096/0.24)*100
= 40 %
Mass of oxygen in the compound = 0.144 g
Therefore % composition by weight of oxygen = (Mass of oxygen/ Total mass of compound)*100
= (0.144/0.24)*100
= 60 %.
The compound is made up of only boron and oxygen, therefore the % composition of the componenets sum to 100% (60% + 40%)
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