A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.096g of boron and 0.144g of oxygen. Calculate the percentage composition of the compound by weight.
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Answer:Mass of the compound = 0.24g
Mass of boron = 0.096g
Mass of oxygen = 0.144g
Percentage of Boron = Mass of boron/ Mass of compound ×100
=0.096g/0.24g×100
=40%
Percentage of oxygen= Mass of oxygen/ masys of compound ×100
=0.144g/0.24g×100=60%
Alternative method
Percentage of oxygen = 100 - percentage of boron
=100-40
=60%
Explanation:
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