Question

a 0.5 kg mass is attached to a string 1m long and is rotated to complete 1 revolution in 0.5 sec. find tension in string

Answer 1

Question

a 0.5 kg mass is attached to a string 1m long and is rotated to complete 1 revolution in 0.5 sec. find tension in string

Answer:T=8N

SOLUTION

The centripetal force for the stone is equal to the tension T in the string

⇒T=$mv^{2} /r$

⇒T=$0.5*4/1$

⇒T=8N

hope this helps u!