Question

A 0.5 m long solenoid has 500 turns and has a flux density of 2.53*10^-3 T at its centre.find current
NEEDED URGENTLY

Answer 1

use the formula for magnetic field by solenoid.
given flux density is nothing but magnetic field only.
I'll explain later in comment in u needed.

Answer 2

Answer:The current is 2.0 A.

Explanation:

Given that,

Magnetic flux density $B = 2.53\times10^{-3}\ T$

Length of solenoid l = 0.5 m

Number of turns N = 500

We know that,

The magnetic flux at its center is

$B = \dfrac{\mu_{0}NI}{l}$

$2.53\times10^{-3} = \dfrac{4\times 3.14\times10^{-7}\times 500\times I}{0.5}$

$I = \dfrac{2.53\times10^{-3}\times0.5}{4\times3.14\times10^{-7}\times 500}$

$I = 2.0 A$

Hence, The current is 2.0 A.