Question

A 0.5 M solution of urea is isotonic with solution of 10 g non-volatile, non-electrolyte unknown solute X in 100 mL of solution. The molar mass of solute is
50 g mol-1
O 100 g mol-1
O 150 g mol-1
O 200 g mol-1​

Answer 1

Answer:

200 g/mol

Explanation:

pls find the attachment

Answer 2

Answer:

200 g/mol

Explanation:

CRT of urea = CRT of solute

C =  moles / volume

0.5  RT= moles / ( 100/1000) x RT

moles = 500/1000

moles =  mass / molar mass

molare mass = 10000/50

                       =200 g/mol

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