A 0.66 kg ball is moving with speed of 100m/s the associated wavelenght will be
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According to the de broglie like radiation (waves) behave like particles
Particles also behave like waves . And he gave a formula. λ = h/p or λ = h/mv
were ,
h -------> Planck's constant
p --------> momentum of an object
m -------> mass of object
v ---------> velocity of an object.
Then why we do not see heavy object like ball behave like waves because
λ is universally proportional to m and v means if mass increase then wavelength is decrease if mass decreases then λ increase so we see this behavior in electron like particles .
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h = 6.626 × 10^-34Js
m = 0.66kg = 66 × 10²Kg
v = 100m/s
λ = ?
λ = h/p
λ = h/mv
λ = 6.626×10^-34/66×10²×10²
λ = 6.626×10^-34/66×10⁴
λ = 0.10039 × 10^-34-4
λ = 0.10039 × 10^-38
λ = 1.0039 × 10^-39m
so associated wavelength = λ = 1.0039 × 10^-39m
Particles also behave like waves . And he gave a formula. λ = h/p or λ = h/mv
were ,
h -------> Planck's constant
p --------> momentum of an object
m -------> mass of object
v ---------> velocity of an object.
Then why we do not see heavy object like ball behave like waves because
λ is universally proportional to m and v means if mass increase then wavelength is decrease if mass decreases then λ increase so we see this behavior in electron like particles .
______________________________________________________________
h = 6.626 × 10^-34Js
m = 0.66kg = 66 × 10²Kg
v = 100m/s
λ = ?
λ = h/p
λ = h/mv
λ = 6.626×10^-34/66×10²×10²
λ = 6.626×10^-34/66×10⁴
λ = 0.10039 × 10^-34-4
λ = 0.10039 × 10^-38
λ = 1.0039 × 10^-39m
so associated wavelength = λ = 1.0039 × 10^-39m
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