A 0.70000000000000007 kg ball is thrown up with an initial velocity of 32 m/s, how much its velocity at the height of 3 m.
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Explanation:
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If there is no air drag then maximum height,
H=2gu2=2×9.8(142)=10m
But due to air drag ball reaches up to height 8m only
So, loss in energy
=mg(10−8)
=0.5×9.8×2
=9.8J
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