A 1.0 hp motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a height of 10m from the ground . The running time of the motor to fill the empty water tank is (g=10) . The answer is 15min .. how????. Please answer ....
Answers
Answered by
106
Power of the motor pump = 1.o hp = 735.5 W
The work done by the motor pump is equal to the change in the potential energy of water when it is pumped from the ground into the overhead water tank.
Let t be the number of seconds that the motor takes to fill the tank. Total height h that water is pumped up is 20m + 10 m = 30 m.
W = P * t = 735.5 * t Joules
ΔPE = m g h
= 2, 238 liters * 1 kg/liter * 10 m/s² * 30 m
= 671, 400 J
W = ΔPE as per Energy conservation (or Work energy)
So 735.5 t = 671, 400
t = 912.84 sec
= 15 minutes 12.84 sec.
The work done by the motor pump is equal to the change in the potential energy of water when it is pumped from the ground into the overhead water tank.
Let t be the number of seconds that the motor takes to fill the tank. Total height h that water is pumped up is 20m + 10 m = 30 m.
W = P * t = 735.5 * t Joules
ΔPE = m g h
= 2, 238 liters * 1 kg/liter * 10 m/s² * 30 m
= 671, 400 J
W = ΔPE as per Energy conservation (or Work energy)
So 735.5 t = 671, 400
t = 912.84 sec
= 15 minutes 12.84 sec.
kvnmurty:
:-)
Answered by
22
Answer:
this is the answer to the question
Attachments:
Similar questions