Question

a 1.0 kg ball is stationary at the top of a hill that is 10.0 meters in height. the ball rolls all the way down the hill. what is its kinetic energy when it reaches the bottom of the hill, assume 10% of energy is lost because of friction and other factors

Answer 1

$\large\sf\underline \purple{ Question }$

A 1.0 kg ball is stationary at the top of a hill that is 10.0 meters in height. the ball rolls all the way down the hill. what is its kinetic energy when it reaches the bottom of the hill, assume 10% of energy is lost because of friction and other factors.

$\large\sf\underline \green{ Answer }$

GIVEN :

The angle theta in the equation is the angle between F and d.

If the F is parallel to the incline and the d is parallel to the incline. Then the angle theta in the work equation is 0 degrees.

For this reason, W=F×d×cos 0°

In each case, the work is approximately 1.18 x 106 Joules.

$\bf \bold{ weight = 1kg }$

$\bf \bold{ Force = let it be x }$

$\bf \bold{ distance = 10m }$

$\sf\large\underline \purple{ Now, \: Applying \: the \: formula }$

${ W=F×d × cos0° }$

${ 1=x × 10° }$

${ x = 10-1 }$

${ x = 9 }$

$\sf{ Now, \: the \: amount \: of \: energy \: lost \: is \: 10percent }$

$\sf{ 10percent = 10/100}$

${ 10 }$ $\sf{ is \: obtained }$

$\sf{ Therefore, \: 10 \: joules \: of \: friction \: and \: other \: factors \: are \: lost }$

$\bf \red{ Mark \: me \: as \: brainlist }$