Question

a)
1.2.4
ii)
Bragg's law is expressed as
d.
Both a and
C.
2k.G+G2=0
b.
2k. G+G=0
2dsin O=Na​

Answer 1

Explanation:

Both a and

C.

2k.G+G2=0

b.

2k. G+G=0

2dsin O=Na