Question

(a +1)^2 + (b+1)^2=0 then find (a^3 +b^3)​

Answer 1

Answer:

the answer I think is -2

Step-by-step explanation:

$({a + 1)}^{2} + {(b + 1)}^{2} = 0 \\ a + 1 = 0 \: \: \: \: \: \: b + 1 = 0 \\ a = - 1 \: \: \: \: \: b = - 1 \\ {a}^{3} + {b}^{3} = { - 1}^{3} + { - 1}^{3} = - 1 + - 1 = - 2$

Answer 2

Step-by-step explanation:

(a+1)²+(b+1)²=0

a²+1+b²+1=0

a²+b²+2=0

a²= -2/-b²

b²= -2/-a²

(a³+b³)

(a+b)³

(a-b) (a²+2ab+b²)