Question

a^1/2 +b^1/2 -c^1/2 =0, then the value of (a+b-c)^2

Answer 1

Given, √a+√b -√c = 0
       ⇒ √a+√b = √c            Squaring on both sides
       ⇒ (√a+√b)² = √c²
       ⇒ a+b+2√ab = c
       ⇒ (a+b-c) = -2√ab

Again squaring on both sides, we get
           (a+b-c)² = (-2√ab)²
       ∴  (a+b-c)² = 4ab

Answer 2

Answer:

Step-by-step explanation:

√a +√b -√c=0

√a+√b= √c

Squaring both sides

(√a+√b)²= √c²

a+b+2√ab =c

a+b-c = -2√ab

Again on squaring

(a+b-c)² = (-2√ab)²

(a+b-c)= 4ab