Question

A 1.2 kilogram basketball travelling at 7.5 metres per second hits the back of a 12 kilogram wagon and bounces off at 3.8 metres per second, sending the wagon off in the original direction of travel of the ball. How fast is the wagon going ?
[Method required]

Answer 1

HEYA!!!!
HERE IS YOUR ANSWER..

M1*V1 + M2*V2 = M1*V3 + M2*V4. 
1.2*7.5 + 12*0 = 1.2*(-3.8) + 12*V4. 
9 + 0 = -4.56 + 12V4. 
12V4 = 13.56. 
V4 = 1.13 m/s. = Velocity of the wagon.

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