Question

A 1.2 m tall girl spots a balloon moving
with the wind in a horizontal line at a
height of 88.2 m from the ground. The
angle of elevation of the balloon from
the eyes of the girl at any instant is
60°. After some time, the angle of
elevation reduces to 30°/see Fig. 9.13).
Find the distance travelled by the
balloon during the interval.​

Answer 1

Step-by-step explanation:

AB=xm

BC=Ym

AC=x+y

EAB=60

IN TRI. Abe

tan60=BE/AB

/3=87/X

X=87//3

IN TRI. ACD

TAN30=CD/AC

1÷/3=87/X+Y

X+Y=87/3

87÷/3+Y=87/3

Y=87/3-87÷/3

Y=87/3-87÷/3

=87×3-87÷/3

=174÷/3

=174×/3÷3

=174×/3÷3

=58×1.73

=100.34m

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