A = {1, 3, 5, 7}, B = {2,3,6,8} à An B = ?
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Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8}
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5}
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2}
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2} Intersection of two sets has the common elements of both the sets.
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2} Intersection of two sets has the common elements of both the sets. ⇒(A−B)∩(A−C)={1} ..... (2)
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2} Intersection of two sets has the common elements of both the sets. ⇒(A−B)∩(A−C)={1} ..... (2)From (1) and (2), we have
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2} Intersection of two sets has the common elements of both the sets. ⇒(A−B)∩(A−C)={1} ..... (2)From (1) and (2), we haveA−(B∪C)=(A−B)∩(A−C)
Answer : Given, A={1,2,3,4,5},B={2,4,6,8} and C={3,4,5,6}For the LHS:Union of two sets will have the elements of both sets.So, B∪C={2,3,4,5,6,8} A−(B∪C) will have elements of A which are not in (B∪C)So, A−(B∪C)={1} ..... (1)For the RHS:A−B will have elements of A which are not in B.So, A−B={1,3,5} A−C will have elements of A which are not in C.So, A−C={1,2} Intersection of two sets has the common elements of both the sets. ⇒(A−B)∩(A−C)={1} ..... (2)From (1) and (2), we haveA−(B∪C)=(A−B)∩(A−C)Hence, the given expression is true.
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