Question

a 1.4 long object is placed perpendicular to principle axis of a convex mirror of length 15 cm at a distance of 10 cm from it
height of the image .
location of the image .
nature of the image​

Answer 1

given, convex mirror so focal length is positive so f=15cm by cartisan sign rule.

object u=-10cm due to cartisan rule

applying mirror formula

1/f = 1/V+1/u

1/15= 1/V - 1/10

1/15+1/10 = 1/V

1/6=1/V

V=6cm

where V is position of image

by magnification formula

m=-V/u = -hi/ho

=> V/u = hi/ho

=> 6/10 = hi/140. (1.4 m = 140cm)

=> hi = 84cm here hi is height of image. CHEERS DUDE