Question

a+1/a=3. a^2+1/a^2=?

Answer 1

Step-by-step explanation:

How can I solve the following problem: If a-1/a=5, then a^2-1/a^2=?

When will Lunchclub be active in Bangalore?

Lunchclub is now virtual and finally open to users in Bangalore! Network from home and make mutually valuable connections locally

supposed to be the right answer in one method,

If a-1/a=5 the a-1=5a

-1=5a-a which is -1=4a which is a=-1/4 ————1

a²-1/a² is (-1/4)² -1/(-1/4)² which is 1/16 -1/1/16.

-15/16 / 1/16

Applying another method from given condition in problem.

Other right answer is a-1/a=5—Eq1

So squaring both sides

We get a² -2a/a +1/a² which is a² +1/a² -2=5×5

Which further is a²+1/a²-2=25—Eq2

Now adding 4 to both sides

a²+1/a²-2+4=25+4

Which is a²+2+1/a²=29

Further square root of both sides

√a²+2+1/a²=√29

a+1/a=√29

Now in problem the then asked what is a²-1/a² is (a+1/a)(a-1/a)

a+1/a ×a-1/a

Whereas in question a-1/a=5 and a+1/a=√29 is proved

So +-5√29 is Answer.

Answer 2

Answer:

given,

a+1/a=3

a^2+1/a^+2=9

a^2+1/a^2 = 9-2=7

pls thanks my ans