a+1/a=3
find the value of (a square + 1/a square)
Answers
Answered by
1
square both sides
and apply (a+b)^2=a^2+b^2+2ab...u will get
a^2+b^2=9-2=7
hope u like
and apply (a+b)^2=a^2+b^2+2ab...u will get
a^2+b^2=9-2=7
hope u like
Answered by
1
(a+1/a)=3
on squaring both the sides,
(a+1/a)^2=3^2
a^2+1/a^2+2*a*1/a=9
a^2+1/a^2+2=9
a^2+1/a^2=9-2
a^2+1/a^2=7
hope it helps.
on squaring both the sides,
(a+1/a)^2=3^2
a^2+1/a^2+2*a*1/a=9
a^2+1/a^2+2=9
a^2+1/a^2=9-2
a^2+1/a^2=7
hope it helps.
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