Question

a+1/a=6 then find the value of a³+1/a³​

Answer 1

Answer:

$Value \:of \: a^{3}+\frac{1}{a^{3}}= 198$

Step-by-step explanation:

$a+\frac{1}{a}=6\:--(1)$

$Value \:of \: a^{3}+\frac{1}{a^{3}}\\=\left(a+\frac{1}{a}\right)^{3}-3\left(a+\frac{1}{a}\right)\\=6^{3}-3\times 6\\=216-18\\=198$

Therefore,

$Value \:of \: a^{3}+\frac{1}{a^{3}}= 198$

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Answer 2

1. Answer:198 is the answer...

${a}^{3} + \frac{1}{a3} = (a + \frac{1}{a} ) {}^{3} - 3 \times a \times \frac{1}{a}(a + \frac{1}{a} ) \\ = (6)^{3} - 3 \times 6 \\ = 216 - 18 \\ = 198$

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