Question

A-1
Adj. Ag
IAT
COS a
sin a
sin a
1-1
COS OC
cos (-a) - sin (-a
sin (0)
cos (-O
Thus each element of G possesses inverse.
Commutative law. Now AqAp= Aq+= Ap+a = AB AQ:
Hence G5 is satisfied.
Thus G is a group under matrix multiplication.
Example 7. If the set S of all ordered pairs (a, b) of
e R and a #0 with respect to the operation "*" defined by
(a, b) * (c,d) = (ac, bc + d)
show that (S, *) is a group.
Solution. G. Closure property. Let (a, b) and (c,d) be an
(a, b) * (c,d)=(ac, bc + d), a 0,c*0, hence a
The nair (cc. bc + d) is such that ac #0, hence if belongs​

Answer 1

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