Question

A-1.
An aeroplane is flying vertically upwards with a uniform speed of 500 m/s. When it is at a height of
1000 m above the ground a shot is fired at it with a speed of 700 m/s from a point directly below it. The
minimum uniform acceleration of the aeroplane now so that it may escape from being hit?
(g = 10 m/s2)
[REE-1994, 6]
(A) 10 m/s2
(B) 8 m/s2
(C) 12 m/s2
(D) None of these​

Answer 1

Answer:

Velocity of bullet with respect to the plane = 700 -500 = 200m/s

Let the acceleration of plane be a.

As the bullet is going upward so acceleration of bullet is g downwards

So acceleration of bullet with respect to the plane = -g-a

                                                           = -10-a

The bullet will not hit the when its velocity is minimum that is v=0

So from v^2 =u^2+2as

0=200 2 +2(-10-a) 1000

0=40000+2000(-10-a)

a= 10m/s2

Hence option A is right.

Answer 2

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