Math, asked by manohar622, 7 months ago

(a+1/b)^3 × (a-1/b)^2 /{(b+1/a)^3 × ( b-1/a)^2​

Answers

Answered by wwwkanishkav
1

Step-by-step explanation:

a^8 b^7-a^7b^6 - 3a^6b^5 + 3a^5b^4 + 3a^4b^3 - 3a^3b^2 - a^2b+ a /a^3 b^8 + 3a^2b^7 + 3ab^6 + b^5

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