a 1 hp motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 litres at height from the ground the running time of the motor to fill the emptytank is (g =10m/s2)
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Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg.
Work = mgh => 2.238*10*20 => 447.6 J
For height 10 m from the ground= > 2.238*10*10 => 223.8 J
Net Energy required = > 447.6 – 223.8 => 223.8 J
1 HP =746 w = 746 J
time required => 223.8/746 => 0.3 seconds
HOPE IT HELPS YOU ☺☺ !!!
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