a 1 microcoulomb charge is uniformly distributed on a spherical shell gives by the equation x^2+ y^2 +z^2=25 what will be the intensity of electric field at a point (1,1,2)?
Answers
a 1 microcoulomb charge is uniformly distributed on a spherical shell gives by the equation x^2+ y^2 +z^2=25 what will be the intensity of electric field at a point (1,1,2)?
answer : option (3) zero.
explanation : we know,
“ charges have nature to reside the outer surface of spherical shell.”
so, inside the spherical shell, electric field intensity becomes zero.
here spherical shell of equation, x² + y² + z² = 25.
point (1,1,2) lies inside the spherical shell as we see (1)² + (1)² + (2)² - 25 < 0
so, electric field intensity at point (1,1,2) will be zero.
Answer:
ans=0
Explanation:
as we know when we give a charge on the spherical cell then charge get distributed on the surface of the spherical shell and inside the spherical shell the electric field is zero because the charges are absent inside the spherical shell from the equation X square + Y square + Y square = 25 the overall value comes to negative that clearly indicate that the point where we have to find the electric field is inside a conductor so we can say that electric field at any inside point of conductor equals to zero