Question

a=1/x-y b=1/x+y
160a+180b=35-----(1)
160a+192b=36-----(2) Please solve each stepwise and with calculation

Answer 1

Answer:

a=1/8

b=1/12

Step-by-step explanation:

By elimination method

Subtracting eqn 1 from 2

12b=1

b=1/12

Substitute value of b in eqn 1

160a+180(1/12)=35

160a+15=35

160a=35-15

160a=20

a=20/160

a=1/8

Answer 2

Step-by-step explanation:

160a+192b=36---(1)

160a+180b=35---(2)

_______________

12b=1

b=1/12

substituting value of 'b' in eqtn (1),

we get, 160a+192×1/12=36

160a=20

a=1/8

______________________

given a=1/x-y and b=1/x+y

1/8=1/x-y & 1/12=1/x+y

x-y=8--(3)& x +y=12---(4)

solving eqtn (3) and (4)

x+y=12

x-y=8

---------------

2x=30

x=10

substituting value of x in (3) or (4)

we get, y=2

----------------------------