(a-1)x²+2x-3=0 has equal roots then the value of a is?
Answers
Given quadratic equation is
On comparing with ax² + bx + c = 0, we get
We know, the quadratic equation ax² + bx + c = 0 have real and equal roots iff Discriminant, D = b² - 4ac = 0
Thus,
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Concept Used :-
Nature of roots :-
Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.
If Discriminant, D > 0, then roots of the equation are real and unequal.
If Discriminant, D = 0, then roots of the equation are real and equal.
If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.
Where,
Discriminant, D = b² - 4ac
Step-by-step explanation:
Given quadratic equation is
On comparing with ax² + bx + c = 0, we get
We know, the quadratic equation ax² + bx + c = 0 have real and equal roots iff Discriminant, D = b² - 4ac = 0
Thus,
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Concept Used :-
Nature of roots :-
Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.
If Discriminant, D > 0, then roots of the equation are real and unequal.
If Discriminant, D = 0, then roots of the equation are real and equal.
If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.
Where,
Discriminant, D = b² - 4ac