Question

A 10.2 mL volume of 0.050 M Mg(NO3)2 contains how much dissolved Mg(NO3)2, in grams?

Answer 1

A 10.2 ml volume of 0.050M mg (NO3)2 contains how much dissolved mg(NO3)2 in grams

Answer 2

Answer: 0.076 grams

Explanation:

Using the formula for molarity, M = moles/L, we find that there are 0.00051 moles of Mg(NO3)2. If we multiply this by the molar mass of Mg(NO3)2, 148.32, we get 0.0756432, rounded to 0.076.