Question

If 3.7 g of Ca(OH)2 is present in 250 mL of aq. solution, the molarity of solution would be


0.2 M


0.35 M


0.5 M


1.2 M

Answer 1

Answer:

Molarity = 0.2M

Explanation:

$Molarity = \frac{Given wt}{Gram Molecular Mass} *\\\frac{1000}{volume(ml)}$

Molarity = (3.7/74)*(1000/250)

               = 0.05*4

               =0.2M

Answer 2

Given:

Mass of Ca(OH)2, w = 3.7 gm

Volume of solution, V = 250 mL

To Find:

Molarity of the given solution, i.e., M.

Calculation:

- The molar mass of Ca(OH)2, M.wt = 74 gm

- The formula of Molarity is given as:

M = (w × 1000) / (M.wt × V)

⇒ M = (3.7 × 1000) / (74 × 250)

⇒ M = 0.2 M

- Hence, the correct answer is option (a) 0.2 M.