(a)
10. 758
05. The product of two numbers is 504347. If one of the numbers is 317, find the other.
76. On dividing 59761 by a certain number, the quotient is 189 and the remainder is 37. F.
the divisor
7. On dividing 55390 by 299, the remainder is 75. Find the quotient using the divis
(а
11. 58
Answers
CORRECT QUESTION :-
(1) The product of two numbers is 504347 . If one of the number is 317 , then find the other number
(2) On dividing 59761 by a certain number , the quotient is 189 and remainder is 37 . Find the divisor
(3) On dividing 55390 by 299 , the remainder is 75 . Find the quotient .
SOLUTION :-
(1) We have ,
- Product of two numbers as 504347
- One of them is 317
Let the other number be 'x'
∴ The other Number is 1591
(2) We are given ,
- dividend = 59761
- divisor = 'a' (let)
- quotient = 189
- Remainder = 27
Relation between Dividend , divisor , quotient and remainder is given by ,
Where ,
- D is dividend
- Q is quotient
- d is divisor
- R is remainder
∴ The certain number is 316
(3) We are given that ,
- Dividend = 55390
- Divisor = 299
- Remainder = 75
- Quotient = 'y' (let)
Relation between Dividend , divisor , quotient and remainder is given by ,
Where ,
- D is dividend
- Q is quotient
- d is divisor
- R is remainder
∴ The quotient is 185
Answer:
CORRECT QUESTION :-
(1) The product of two numbers is 504347 . If one of the number is 317 , then find the other number
(2) On dividing 59761 by a certain number , the quotient is 189 and remainder is 37 . Find the divisor
(3) On dividing 55390 by 299 , the remainder is 75 . Find the quotient .
SOLUTION :-
(1) We have ,
Product of two numbers as 504347
One of them is 317
Let the other number be 'x'
\begin{gathered} \implies \bf \: x \times 317 = 504347 \\ \\ \implies \bf \: 317x = 504347 \\ \\ \implies \bf \: x = \frac{504347}{317} \\ \\ \implies {\underline {\boxed {\blue {\bf{x = 1591}}}}}\end{gathered}
⟹x×317=504347
⟹317x=504347
⟹x=
317
504347
⟹
x=1591
∴ The other Number is 1591
(2) We are given ,
dividend = 59761
divisor = 'a' (let)
quotient = 189
Remainder = 27
Relation between Dividend , divisor , quotient and remainder is given by ,
\large {\underline {\boxed {\red {\bf{ D = d \times Q + R}}}}}
D=d×Q+R
Where ,
D is dividend
Q is quotient
d is divisor
R is remainder
\begin{gathered} \implies \bf \: 59761 = x \times 189 + 37 \\ \\ \implies \bf \: 59761 = 189x + 37 \\ \\ \implies \bf \: 59761 - 37 = 189x \\ \\ \implies \bf \: 59724 = 189x \\ \\ \implies \bf \: x = \frac{59724}{189} \\ \\ \implies {\underline {\boxed {\blue {\bf{x = 316}}}}}\end{gathered}
⟹59761=x×189+37
⟹59761=189x+37
⟹59761−37=189x
⟹59724=189x
⟹x=
189
59724
⟹
x=316
∴ The certain number is 316
(3) We are given that ,
Dividend = 55390
Divisor = 299
Remainder = 75
Quotient = 'y' (let)
Relation between Dividend , divisor , quotient and remainder is given by ,
\large {\underline {\boxed {\red {\bf{ D = d \times Q + R}}}}}
D=d×Q+R
Where ,
D is dividend
Q is quotient
d is divisor
R is remainder
\begin{gathered} \implies \bf \: 55390 = 299 \times y + 75 \\ \\ \implies \bf \: 55390 = 299y + 75 \\ \\ \implies \bf \: 55390 - 75 = 299y \\ \\ \implies \bf \: 55315 = 299y \\ \\ \implies \bf \: y = \frac{55315}{299} \\ \\ \implies {\underline {\boxed {\blue {\bf{ \: y = 185}}}}}\end{gathered}
⟹55390=299×y+75
⟹55390=299y+75
⟹55390−75=299y
⟹55315=299y
⟹y=
299
55315
⟹
y=185
∴ The quotient is 185