A 10 cm long object is placed at 15 cm away from a convex mirror of focal length 10 cm.find the height ,magnification and position of the image. (
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It is to be remembered that a convex mirror always forms the virtual, erect and diminished image.
Given: Object distance, u=−10cm Focal length, f=15cm
To find: Image distance, v
From mirror formula :
v
1
+
u
1
=
f
1
v
1
−
10
1
=
15
1
v
1
=
15
1
+
10
1
=
150
25
v=6cm
Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification
m=
u
−v
=
−10
−6
=0.6
Hence it will be erect and diminished.
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