Question

A 10 cm long solenoid is meant to have a magnetic field 0.002T inside it, when a current of 3A flows through it. Calculate the required no. of turns.

Answer 1

Answer ⇒ 53 turns.

Explanation ⇒ Given conditions,

 Length = 10 cm.

B = 0.002 T.

Current(i) = 3 A

Using the formula,

   B = μ₀N/l × i

∴ 0.002 = 4π × 10⁻⁷ × N/0.1 × 3

N = 2/3 × 10³/4π

∴ N = 0.05303 × 1000

∴ N ≈ 53 turns.

Thus,

No. of turns in the long solenoid is 53 turns.

Hope it helps.

Answer 2

Answer:

Explanation:B = μ₀N/l × i

∴ 0.002 = 4π × 10⁻⁷ × N/0.1 × 3

N = 2/3 × 10³/4π

∴ N = 0.05303 × 1000

∴ N ≈ 53 turns.